In an attempt to better understand the State monad in Scala I wanted to do something practical with it. One thought that came to mind was a simple Monte Carlo simulation to estimate the constant π.

To estimate π using a Monte Carlo simulation we can randomly sample x and y values within a square centered around 0 to see if they land inside r^2. If x^2 + y^2 <= r^2 then the point is inside of the circle. We can then plug this amount into the formula for the ratio of the area of a circle enclosed in a square which is:

If we solve for π using our simulation result as the ratio of the area we get:

Let’s illustrate this random sampling for the ratio of points within the circle graphically in R:

set.seed(42)
runs = 10000
xs = runif(runs, min=-1, max=1)
ys = runif(runs, min=-1, max=1)
inside = xs^2 + ys^2 <= 1
df = data.frame(x=xs, y=ys, inside=inside)
estimate = sum(inside)/runs*4
ggplot(df, aes(x=x, y=y, color=inside)) +
geom_point() +
scale_color_hue(l=50) +
labs(title=paste('Monte Carlo Simulation for Pi: ',estimate))


This gives us a plot of the circle with the random points that fell inside the differentiated from those that fell outside: When I started thinking about this problem I was a little stumped regarding how to feed a pure random number generator through a Scala for comprehension while also accumulating the number of points within the circle.

I wanted to be able to pull a pair of x and y values from a pure random number generator using a for comprehension to describe the simulation. I was imagining something like the following:

for {
x <- nextDouble
y <- nextDouble
isInCircle = (x * x + y * y) < 1.0
}


But I wasn’t sure how to accumulate the rolling ratio of coordinates within the unit circle. With a little help from Stackoveflow I was able to sort it out.

Once I got some help from SO, I had the pieces I needed to put it together. The first piece we’ll need is a pure random number generator. We’ll call it RNG:

object RNG {
type RNG[A] = State[Long, A]
def nextLong: RNG[Long] =
State.modify[Long](
seed => (seed * 0X5DEECE66DL + 0XBL) & 0XFFFFFFFFFFFFL
) >> State.get

def nextInt: RNG[Int] = nextLong.map(l => (l >>> 16).toInt)

def nextNatural: RNG[Int] = nextInt.map { i =>
if (i > 0) i
else if (i == Int.MinValue) 0
else i + Int.MaxValue
}

def nextDouble: RNG[Double] = nextNatural.map(_.toDouble / Int.MaxValue)

def runRng[A](seed: Long)(rng: RNG[A]): A = rng.runA(seed).value

def unsafeRunRng[A]: RNG[A] => A = runRng(System.currentTimeMillis)
}


The key method for the purpose of generating random numbers for our Monte Carlo simulation is the nextDouble method. This is what we’ll use to generate a pair of x and y values.

The real insight from the SO post is the step function which allows us to accumulate the rolling ratio of coordinates within the circle. We’ll break out of our iteration or continue by signalling with Right or Left values respectively. This is handled for us via the tailRecM function on the Monad trait in cats.

With nextDouble and the step pattern we can now implement our simulator:

case class Step(count: Int, inCircle: Int)

def calculatePi(iterations: Int): RNG[Double] = {
def step(s: Step): RNG[Either[Step, Double]] =
for {
x <- nextDouble
y <- nextDouble
isInCircle = (x * x + y * y) < 1.0
newInCircle = s.inCircle + (if (isInCircle) 1 else 0)
} yield {
if (s.count >= iterations)
Right(s.inCircle.toDouble / s.count.toDouble * 4.0)
else
Left(Step(s.count + 1, newInCircle))
}

}


I put everything together in a repo on github. To run it:

sbt -warn "run 100000"
Estimated 3.14916 for Pi after 100000 iterations.
[success] Total time: 2 s, completed


Though the State monad is fairly simple on the surface there’s a lot going on underneath in cats. For example, a naive implementation of State.flatMap would not be able to support 10,000 iterations of our simulation because it’s not stack safe. The for comprehension would create nested instances of flatMap that would eventually exhaust the call stack. The tailRecM method enables stack-less recursion for monads on the JVM. If you’re interested in learning more see this paper by Rúnar Bjarnason. He’s one of the authors of Functional Programming in Scala.

As a final thought, you may be thinking that there are easier ways to estimate π and you would be right. One of the insights that came out of the Basel Problem from Euler is a series that can be use to estimate π. In R it looks like:

s = seq(1, 10000)
sqrt(sum(1/s^2)*6)
 3.141497


Or in Scala:

Math.sqrt((1 to 10000).foldLeft(0.0)((t, x) => t + 1/Math.pow(x, 2))*6)
res1: Double = 3.1414971639472147


I’m sure there are others.